Hydraulic Learning

Calculating a Pump’s Maximum Suction Head

Calculating Maximum Suction Head

Calculating a Pump's Maximum Suction Head

Context: One of the biggest challenges in hydraulics is ensuring a pump operates correctly by avoiding the destructive phenomenon of cavitationThe formation of vapor bubbles in a liquid when the local pressure drops below its vapor pressure. The implosion of these bubbles can damage components..

This occurs when the pressure at the pump's inlet drops below the liquid's vapor pressure. To prevent it, it is crucial to calculate the maximum geometric height (or "suction lift") at which a pump can be placed above the free surface of the liquid. This exercise will guide you through calculating the NPSH AvailableNet Positive Suction Head Available (NPSHa). This is the absolute pressure head at the pump's inlet, above the liquid's vapor pressure. It is a characteristic of your system/installation. (NPSHa) of the installation to determine this maximum height.

Learning Note: This exercise will teach you to apply Bernoulli's equation to a real-world pumping system, accounting for pressures (head), velocity, and head loss to ensure a reliable and durable installation.


Learning Objectives

  • Understand the phenomenon of cavitation and its causes.
  • Define and differentiate NPSH Available (NPSHa) and NPSH RequiredNet Positive Suction Head Required (NPSHr). This is the minimum pressure head required at the pump's inlet to prevent cavitation. It is a characteristic provided by the pump manufacturer. (NPSHr).
  • Calculate all components of NPSHa: pressure head, velocity head, and head losses.
  • Determine the maximum geometric suction head for a given installation.

Problem Data

A centrifugal pump is used to draw water from a large reservoir open to the atmosphere. The objective is to determine the maximum height (\(H_s\)) at which the pump can be installed above the water level without risk of cavitation.

Pumping Installation Diagram
P atm Reservoir (Level 1) Pump Point 2 Hâ‚›
Characteristic Symbol Value
Atmospheric Pressure \(P_{\text{atm}}\) 14.7 psi (at sea level)
Water Temperature \(T\) 70 °F
Pump NPSH Required \(\text{NPSH}_r\) 10.0 ft
Parameter Symbol Value Unit
Volumetric Flow Rate \(Q_v\) 440 GPM
Suction Pipe Diameter \(D\) 4.0 in
Total Pipe Length \(L\) 25 ft
Linear Head Loss Coefficient \(\lambda\) 0.02 -

Problem Questions

  1. Calculate the water velocity in the suction piping.
  2. Calculate the total head loss (\(\Delta H_T\)) in the suction piping.
  3. Write the literal equation for the NPSH Available (NPSHa) at the pump.
  4. Determine the maximum allowable suction head (\(H_{s, \text{max}}\)).

Fundamentals: NPSH and Cavitation

To solve this problem, we will rely on Bernoulli's equation and the definition of NPSH, all expressed in terms of "head" (feet of fluid).

1. Bernoulli's Equation (in terms of Head)
This expresses the conservation of energy for a moving fluid. Between the free surface of the reservoir (point 1) and the pump inlet (point 2), it is written: \[ h_1 + \frac{v_1^2}{2g} + z_1 = h_2 + \frac{v_2^2}{2g} + z_2 + \Delta H_{\text{T}(1 \to 2)} \] Where \(h\) is the pressure head (\(P/\gamma\)), \(v^2/2g\) is the velocity head, and \(z\) is the elevation head.

2. NPSH Available (NPSHa)
NPSHa represents the absolute energy head at the pump inlet above the liquid's vapor pressure head. It is calculated from the system's characteristics. \[ \text{NPSH}_a = \frac{P_{\text{inlet, abs}}}{\gamma} - \frac{P_{\text{vapor}}}{\gamma} = \left( h_{\text{inlet, static}} + \frac{v_{\text{inlet}}^2}{2g} \right) - h_{\text{vapor}} \] To prevent cavitation, it is essential that: \(\text{NPSH}_a > \text{NPSH}_r\). We will use a safety margin.


Solution: Calculating Maximum Suction Head

Question 1: Calculate the water velocity in the suction piping.

Principle

The velocity of the fluid in a pipe is directly related to the volumetric flow rate and the cross-sectional area of the pipe. This is a direct application of the conservation of mass (or flow rate) for an incompressible fluid.

Mini-Course

The continuity equation states that for an incompressible fluid, the volumetric flow rate (\(Q_v\)) is constant. This flow rate is the product of the pipe's cross-sectional area (\(A\)) and the average fluid velocity (\(v\)) through that section. Therefore, if we know the flow rate and the pipe geometry, we can find the velocity.

Pedagogical Note

The most critical step in this type of calculation is unit management. Flow rates are often in Gallons Per Minute (GPM) and diameters in inches (in). It is imperative to convert everything to standard US customary units (ft³/s and ft) before applying the formula to avoid errors.

Standards

This calculation is based on fundamental physics. However, many piping design standards (like ASME B31.3) recommend maximum velocities for fluids (typically 5-10 ft/s for water) to limit erosion, noise, and vibration.

Formula(s)

Velocity-Flow Rate Relation

\[ v = \frac{Q_v}{A} = \frac{Q_v}{(\pi \cdot D^2 / 4)} = \frac{4 \cdot Q_v}{\pi \cdot D^2} \]
Assumptions
  • The fluid (water) is considered incompressible.
  • The flow is steady (flow rate does not vary over time).
  • The calculated velocity is an average velocity over the pipe's cross-section.
Given Data

We must first convert the units to be consistent (ft³/s and ft).

ParameterSymbolValueUnitConversion (US Customary)
Volumetric Flow Rate\(Q_v\)440GPM\(440 / (7.4805 \times 60) \approx 0.9804 \text{ ft}^3/\text{s}\)
Diameter\(D\)4.0in\(4.0 / 12 = 0.3333 \text{ ft}\)
Tips

The conversion `1 GPM ≈ 0.002228 ft³/s` is useful, but it's often more intuitive to remember `1 ft³ ≈ 7.48 gal`. A velocity of 11.23 ft/s is quite high for a suction line, where velocities are typically kept below 5-7 ft/s to minimize head loss.

Diagram (Before Calculation)
Pipe Cross-Section
RDQv, v
Calculation(s)

Step 1: Unit Conversion

First, convert all inputs to base US customary units (feet and seconds).

\[ \begin{aligned} \text{Flow Rate } Q_v &= 440 \text{ GPM} \\ &= \frac{440 \text{ gal}}{1 \text{ min}} \times \frac{1 \text{ ft}^3}{7.4805 \text{ gal}} \times \frac{1 \text{ min}}{60 \text{ s}} \\ &\approx 0.9804 \text{ ft}^3/\text{s} \end{aligned} \]
\[ \begin{aligned} \text{Diameter } D &= 4.0 \text{ in} \\ &= \frac{4.0}{12} \text{ ft} \\ &\approx 0.3333 \text{ ft} \end{aligned} \]

Step 2: Apply Velocity Formula

Now, we apply the continuity equation: \( v = \frac{4 \cdot Q_v}{\pi \cdot D^2} \).

\[ \begin{aligned} v &= \frac{4 \times 0.9804 \text{ ft}^3/\text{s}}{\pi \times (0.3333 \text{ ft})^2} \\ &= \frac{3.9216}{\pi \times 0.1111} \\ &= \frac{3.9216}{0.34907} \\ &\approx 11.23 \text{ ft/s} \end{aligned} \]
Diagram (After Calculation)
Flow Visualization
Pipingv
Reflections

A velocity of 11.23 ft/s is quite high for a suction line, which suggests significant head loss will occur. In a real-world design, one might consider increasing the pipe diameter (e.g., to 5 or 6 inches) to reduce this velocity and thus increase the safety margin against cavitation.

Key Points

The most common mistake is forgetting to square the diameter in the formula. Another frequent error is mixing units (e.g., using inches and feet, or GPM and ft/s, in the same equation). Always convert to base units first.

Points to Remember
  • Velocity is inversely proportional to the square of the diameter (\(v \propto 1/D^2\)).
  • The continuity equation (\(Q_v=A \cdot v\)) is a fundamental tool.
  • Correct unit conversion is the essential first step in any calculation.
Did you know?

The Irish engineer Osborne Reynolds, in the 19th century, conducted crucial experiments showing the transition between laminar (orderly) and turbulent (chaotic) flow. At 11.23 ft/s in a 4-inch pipe, this water flow is highly turbulent.

FAQ
Final Result
The water velocity in the suction piping is approximately 11.23 ft/s.
Try It Yourself

What flow rate (in GPM) would be required to keep the velocity at 7.0 ft/s in the same pipe?

Question 2: Calculate the total head loss (\(\Delta H_{\text{T}}\)) in the suction piping.

Principle

Head loss represents the energy "lost" by the fluid, converted into heat due to friction against the pipe walls (linear head loss) and turbulence from fittings like elbows or valves (minor head loss). Here, we are only calculating the linear (frictional) head loss for simplicity.

Mini-Course

The Darcy-Weisbach equation is the standard formula for calculating linear head loss. It relates the head loss (\(\Delta H\)) to the fluid velocity (\(v\)), pipe diameter (\(D\)), and pipe length (\(L\)) via a dimensionless friction factor, \(\lambda\) (lambda), which depends on pipe roughness and the flow regime (Reynolds number).

Pedagogical Note

Note the dependence of head loss on the *square* of the velocity (\(v^2\)). This means if you double the flow rate (and thus velocity), you *quadruple* the frictional head loss! This is the most influential factor in hydraulic system design.

Standards

Calculating head loss is standard engineering practice. The friction factor \(\lambda\) is often determined using the Colebrook-White equation, which is the basis for the Moody diagram. These methods are recommended by many international standards for piping system design.

Formula(s)

Darcy-Weisbach Equation

\[ \Delta H_{\text{T}} = \lambda \cdot \frac{L}{D} \cdot \frac{v^2}{2g} \]
Assumptions
  • Only linear (friction) losses are considered (neglecting the reservoir exit, strainer, and elbow).
  • The friction factor \(\lambda\) is constant along the entire pipe.
  • The acceleration of gravity \(g\) is taken as 32.2 ft/s².
Given Data

We use the data from the problem and the result from Question 1.

ParameterSymbolValueUnit
Friction Factor\(\lambda\)0.02-
Length\(L\)25ft
Diameter\(D\)0.3333ft
Velocity\(v\)11.23ft/s
Tips

The term \(v^2/(2g)\) is called the "velocity head." It's often useful to calculate it separately, as it reappears in many hydraulic calculations. Here, it is 1.958 ft, which is a significant value.

Diagram (Before Calculation)
Head Loss Visualization
Energy Grade Line (EGL) along pipeEGLPipe (L=25ft)ΔH_T ?
Calculation(s)

Step 1: Calculate the Velocity Head (\(v^2/2g\))

This term represents the kinetic energy of the fluid, expressed in feet of head. We use the velocity from Q1 (\(v \approx 11.23 \text{ ft/s}\)) and \(g \approx 32.2 \text{ ft/s}^2\).

\[ \begin{aligned} \frac{v^2}{2g} &= \frac{(11.23 \text{ ft/s})^2}{2 \times 32.2 \text{ ft/s}^2} \\ &= \frac{126.11}{64.4} \\ &\approx 1.958 \text{ ft} \end{aligned} \]

Step 2: Calculate the Head Loss (\(\Delta H_{\text{T}}\))

We now apply the Darcy-Weisbach formula using our known values: \(\lambda = 0.02\), \(L = 25 \text{ ft}\), \(D = 0.3333 \text{ ft}\), and the velocity head (\(v^2/2g \approx 1.958 \text{ ft}\)).

\[ \begin{aligned} \Delta H_{\text{T}} &= \lambda \cdot \frac{L}{D} \cdot \frac{v^2}{2g} \\ &= 0.02 \times \left( \frac{25 \text{ ft}}{0.3333 \text{ ft}} \right) \times (1.958 \text{ ft}) \\ &= 0.02 \times 75 \times 1.958 \\ &= 1.5 \times 1.958 \\ &\approx 2.937 \text{ ft} \end{aligned} \]

We have therefore lost approximately 2.94 feet of head (energy) due to friction over the 25-foot pipe. This value will be subtracted from the available energy at the suction.

Diagram (After Calculation)
Energy Loss Illustration
Energy Grade Line (EGL) along pipeEGLPipingLoss
Reflections

Losing almost 3 feet of head over just 25 feet of pipe confirms that our velocity of 11.23 ft/s is high and has a major impact. In a real-world scenario, minor losses (from the strainer, elbow, etc.) would add to this figure, further reducing the possible suction height.

Key Points

Don't forget the acceleration of gravity, \(g\), in the velocity head term. Ensure that \(L\) and \(D\) are in the same unit (feet) so the ratio \(L/D\) is dimensionless. The result \(\Delta H_T\) is a height, so its unit is feet.

Points to Remember
  • Head loss is an energy "tax" for moving fluid.
  • The Darcy-Weisbach equation is the standard tool for linear losses.
  • Head loss increases with length and velocity, and decreases with diameter.
Did you know?

The Moody diagram, developed in 1944 by Lewis Ferry Moody, is a graph that plots the friction factor \(\lambda\) against the Reynolds number and the relative roughness of the pipe. Before calculators, this diagram was an essential tool for all fluid mechanics engineers.

FAQ
Final Result
The total linear head loss in the suction piping is approximately 2.94 ft.
Try It Yourself

Keeping the same velocity, what would the head loss be if the pipe were 50 ft long?

Question 3: Write the literal equation for the NPSH Available (NPSHa).

Principle

NPSHa is determined by applying the Bernoulli energy balance equation between the liquid surface in the reservoir (where conditions are known) and the pump inlet (the point of interest). It represents the total absolute head available at the suction, minus the vapor pressure head.

Mini-Course

Bernoulli's equation is key: \(h_1 + \frac{v_1^2}{2g} + z_1 = h_2 + \frac{v_2^2}{2g} + z_2 + \Delta H_{\text{T}}\). The definition of NPSHa is \(\text{NPSH}_a = h_2 + \frac{v_2^2}{2g} - h_v\). The method is to isolate the term for the total energy at the inlet, \(\left( h_2 + \frac{v_2^2}{2g} \right)\), from Bernoulli's, and substitute it into the NPSHa definition.

Pedagogical Note

The choice of points 1 and 2 is strategic. We always choose a point 1 where we know the most information (here, the surface of a large reservoir at atmospheric pressure with zero velocity) to simplify the equation and easily isolate the unknown at point 2.

Standards

Applying Bernoulli's equation is a fundamental law of physics. The definitions of NPSH are standardized by organizations like the Hydraulic Institute (HI), ensuring all engineers and manufacturers use the same terminology.

Formula(s)

Bernoulli's Equation (Head)

\[ h_1 + \frac{v_1^2}{2g} + z_1 = h_2 + \frac{v_2^2}{2g} + z_2 + \Delta H_{\text{T}} \]

Definition of NPSH Available

\[ \text{NPSH}_a = h_2 + \frac{v_2^2}{2g} - h_v \]
Assumptions
  • The pressure head at the reservoir surface (point 1) is the atmospheric pressure head (\(h_1 = h_{\text{atm}} = P_{\text{atm}}/\gamma\)).
  • The velocity at the surface of a large reservoir is considered negligible (\(v_1 \approx 0\)).
  • We set the reference elevation \(z=0\) at the water surface, so \(z_1=0\). The pump inlet is at an elevation \(z_2 = H_s\).
Given Data

This is a literal derivation, so the data consists of the symbols: \(h_{\text{atm}}, h_v, g, H_s, v, \Delta H_{\text{T}}\).

Tips

Think of NPSHa as an energy "budget." The source is the atmospheric pressure head (\(h_{\text{atm}}\)). You "spend" this budget by lifting the water (\(H_s\)) and overcoming friction (\(\Delta H_T\)). What remains must be greater than the liquid's vapor pressure head (\(h_v\)) plus the pump's requirement (\(\text{NPSH}_r\)).

Diagram (Before Calculation)
Points for Bernoulli's Equation
Point 1Point 2
Calculation(s)

Step 1: Simplify Bernoulli's Equation

We apply our assumptions (\(h_1 = h_{\text{atm}}\), \(v_1 = 0\), \(z_1 = 0\), \(z_2 = H_s\)) to the main equation:

\[ h_{\text{atm}} + 0 + 0 = h_2 + \frac{v_2^2}{2g} + H_s + \Delta H_{\text{T}} \]

Step 2: Isolate the Total Inlet Head

The definition of NPSHa uses the term \(\left( h_2 + \frac{v_2^2}{2g} \right)\), which is the total head at the pump inlet. Let's solve for this term:

\[ h_2 + \frac{v_2^2}{2g} = h_{\text{atm}} - H_s - \Delta H_{\text{T}} \]

Step 3: Substitute into the NPSHa Definition

Now we replace the \(\left( h_2 + \frac{v_2^2}{2g} \right)\) term in the NPSHa definition: \(\text{NPSH}_a = \left( h_2 + \frac{v_2^2}{2g} \right) - h_v\)

\[ \text{NPSH}_a = \left( h_{\text{atm}} - H_s - \Delta H_{\text{T}} \right) - h_v \]

Rearranging for clarity gives the final, fundamental equation:

\[ \text{NPSH}_a = h_{\text{atm}} - h_v - H_s - \Delta H_{\text{T}} \]

This equation shows that the NPSH Available is the atmospheric head, minus the vapor pressure head, minus the static lift, minus the friction losses.

Diagram (After Calculation)
Head Balance Diagram
h_atm=NPSHa+Hs+ΔH T+h_v
Reflections

This final equation is fundamental. It clearly shows that NPSHa (the system's contribution) decreases if: the suction head \(H_s\) increases, the head loss \(\Delta H_T\) increases (longer pipe, higher velocity), atmospheric pressure \(h_{\text{atm}}\) decreases (high altitude), or vapor pressure \(h_v\) increases (hotter liquid).

Key Points

Be careful not to confuse terms. \(H_s\) is a geometric elevation, while all other terms (\(h_{\text{atm}}\), \(h_v\), \(\Delta H_T\)) are energy heads. Maintaining consistent signs and units (all in feet) is crucial throughout the derivation.

Points to Remember

\(\text{NPSH}_a\) = (Absolute Source Pressure Head) - (Geometric Lift) - (Total Head Losses). This is the energy balance for the suction line.

Did you know?

Evangelista Torricelli's work on the barometer in the 17th century first demonstrated that the atmosphere has weight and exerts pressure. It is this atmospheric pressure (head) that "pushes" the water up into the pump. A pump doesn't "suck"; it creates a low-pressure zone, and the atmosphere pushes the fluid in.

FAQ
Final Result
The literal equation for NPSH Available is: \[\text{NPSH}_a = h_{\text{atm}} - h_v - H_s - \Delta H_{\text{T}}\]
Try It Yourself

If the reservoir was closed and pressurized to a head of \(h_{\text{res}}\), how would the equation change? (replace the incorrect term)

Question 4: Determine the maximum allowable suction head (\(H_{s, \text{max}}\)).

Principle

The maximum height is reached at the physical limit of correct operation, i.e., just before cavitation begins. This condition is defined when the NPSH Available from the system is exactly equal to the NPSH Required by the pump, plus a safety margin to cover uncertainties.

Mini-Course

The \(\text{NPSH}_r\) is an intrinsic characteristic of the pump, provided by the manufacturer. It represents the minimum energy head the fluid must have at the inlet for the pump to operate without cavitating. Calculating \(H_{s, \text{max}}\) involves using the \(\text{NPSH}_a\) equation from Q3, setting \(\text{NPSH}_a = \text{NPSH}_r + \text{Margin}\), and then solving for the unknown \(H_s\).

Pedagogical Note

This calculation is the culmination of the exercise. It transforms a series of theoretical principles (Bernoulli, head loss) into a concrete, practical value for an installer: "Do not place the pump more than X feet above the water." This is the essence of engineering design.

Standards

The Hydraulic Institute (HI) is a primary reference for this. Their standards, like ANSI/HI 9.6.1, recommend safety margins between NPSHa and NPSHr. A margin of 2-3 feet is common practice, but it may be larger for critical applications or difficult liquids.

Formula(s)

Cavitation Limit Condition

\[ \text{NPSH}_a = \text{NPSH}_r + \text{Margin} \]

Maximum Suction Head Equation

\[ H_{s, \text{max}} = (h_{\text{atm}} - h_v) - \Delta H_{\text{T}} - (\text{NPSH}_r + \text{Margin}) \]
Assumptions
  • The provided data (flow rate, NPSHr, fluid properties) are accurate for the operating conditions.
  • We will use a conservative safety margin of **2.0 ft**.
Given Data

We need the properties of water at 70°F and the results from the previous questions.

ParameterSymbolValueUnit
Atmospheric Pressure\(P_{\text{atm}}\)14.7psi
Vapor Pressure of Water (70°F)\(P_v\)0.363psi
Specific Weight of Water (70°F)\(\gamma\)62.3lb/ft³
Head Loss\(\Delta H_{\text{T}}\)2.937ft
NPSH Required\(\text{NPSH}_r\)10.0ft
Safety Margin\(\text{Margin}\)2.0ft
Tips

The term \(h_{\text{atm}}\) (atmospheric head) is the theoretical maximum height water can be lifted by a perfect vacuum at sea level. \(h_{\text{atm}} = P_{\text{atm}}/\gamma = (14.7 \times 144) / 62.3 \approx 33.95 \text{ ft}\). All "expenses" (vapor pressure, friction, pump requirement) are subtracted from this total budget.

Diagram (Before Calculation)
Head Budget Balance
h_atmh_vΔH TNPSHrMarginHs,max?
Calculation(s)

Step 1: Calculate Net Pressure Head Available

This is the term \((h_{\text{atm}} - h_v)\). It represents the maximum head the atmosphere can provide, accounting for the liquid's tendency to boil.

  • \(P_{\text{atm}} = 14.7 \text{ psi}\)
  • \(P_v = 0.363 \text{ psi}\)
  • \(\gamma = 62.3 \text{ lb/ft}^3\)
  • Conversion: \(1 \text{ psi} = 144 \text{ lb/ft}^2\) (psf)

First, let's find the head for each pressure term:

\[ \begin{aligned} h_{\text{atm}} &= \frac{P_{\text{atm}}}{\gamma} = \frac{14.7 \text{ lb/in}^2 \times 144 \text{ in}^2/\text{ft}^2}{62.3 \text{ lb/ft}^3} \\ &= \frac{2116.8 \text{ psf}}{62.3 \text{ lb/ft}^3} \approx 33.98 \text{ ft} \end{aligned} \]
\[ \begin{aligned} h_v &= \frac{P_v}{\gamma} = \frac{0.363 \text{ lb/in}^2 \times 144 \text{ in}^2/\text{ft}^2}{62.3 \text{ lb/ft}^3} \\ &= \frac{52.27 \text{ psf}}{62.3 \text{ lb/ft}^3} \approx 0.839 \text{ ft} \end{aligned} \]

The net pressure head is:

\[ \begin{aligned} (h_{\text{atm}} - h_v) &= 33.98 \text{ ft} - 0.839 \text{ ft} \\ &\approx 33.14 \text{ ft} \end{aligned} \]

Step 2: Calculate Maximum Suction Head (\(H_{s, \text{max}}\))

We now use the final formula, subtracting all "costs" from our available net pressure head:

\[ H_{s, \text{max}} = (h_{\text{atm}} - h_v) - \Delta H_{\text{T}} - \text{NPSH}_r - \text{Margin} \]

Substitute all our values:

  • Net Pressure Head \((h_{\text{atm}} - h_v)\) = 33.14 ft (from Step 1)
  • \(\Delta H_{\text{T}} = 2.937 \text{ ft}\) (from Question 2)
  • \(\text{NPSH}_r = 10.0 \text{ ft}\) (Given)
  • \(\text{Margin} = 2.0 \text{ ft}\) (Assumed)
\[ \begin{aligned} H_{s, \text{max}} &= 33.14 \text{ ft} - 2.937 \text{ ft} - 10.0 \text{ ft} - 2.0 \text{ ft} \\ &= 33.14 - (2.937 + 10.0 + 2.0) \\ &= 33.14 - 14.937 \\ &= 18.203 \text{ ft} \end{aligned} \]
Diagram (After Calculation)
Final Head Distribution
Total HeadHs,maxAvailableMarginNPSHrΔH Th_v
Reflections

This result means that for this specific installation and flow rate, the pump's inlet must not be placed more than 18.2 feet above the water level. Any higher, and the pressure at the pump inlet will drop too low, causing the water to boil (cavitate), which will quickly destroy the pump.

Key Points

Ensure all "costs" (head loss, NPSHr, margin) are subtracted from the net available pressure head. A sign error is easy to make and will lead to a physically impossible result. The maximum suction head must always be less than the barometric head (~34 ft for water).

Points to Remember

The maximum suction head is a budget: what the atmosphere provides, minus what the system consumes (losses, pump requirement, safety margin). This is the most critical design calculation for the longevity of a centrifugal pump.

Did you know?

To pump very hot liquids (near their boiling point), the vapor pressure head \(h_v\) is almost equal to the ambient pressure, making the net pressure head nearly zero. In these cases (e.g., boiler feedwater), the tank is placed high above the pump so that \(H_s\) is negative (a "flooded suction"), providing the necessary energy to the pump.

FAQ
Final Result
The maximum allowable suction head, including a 2.0 ft safety margin, is 18.20 ft.
Try It Yourself

What would the new maximum height be if the pump was replaced with a high-performance model with an \(\text{NPSH}_r\) of only 5.0 ft?


Interactive Tool: Suction Head Simulator

Use the sliders to see how water temperature and suction pipe length affect the pump's maximum installation height.

Input Parameters
70 °F
25 ft
Key Results
Head Budget (ft) -
Max Suction Head (ft) -

Final Quiz: Test Your Knowledge

1. What is cavitation?

  • The formation and implosion of vapor bubbles in the pumped liquid.
  • A normal operating sound of a pump at high speed.

2. What is the essential condition to prevent cavitation?

  • \(\text{NPSH}_a > \text{NPSH}_r\)

3. If the water temperature increases, what happens?

  • The maximum suction head decreases.
  • The maximum suction head increases.
  • It has no effect on the suction head.

4. The NPSH Required (NPSHr) depends on:

  • The pump's design (a manufacturer specification).
  • The atmospheric pressure.

5. Increasing the suction pipe diameter (at a constant flow rate) will:

  • Decrease the NPSH available.
  • Have no effect on the NPSH available.
  • Increase the NPSH available.

Cavitation
The phenomenon of a liquid boiling due to a local pressure drop, creating vapor bubbles that violently implode when they reach a higher pressure zone, causing noise, vibration, and material erosion.
NPSH (Net Positive Suction Head)
A measure of the pressure margin at a pump's inlet to prevent cavitation. NPSHa (Available) is a system property; NPSHr (Required) is a pump property.
Vapor Pressure (\(P_v\))
The pressure at which a liquid will boil at a given temperature. It increases sharply with temperature.
Head Loss (\(\Delta H_T\))
Energy (expressed in feet of fluid) lost by a moving fluid, primarily due to friction against pipe walls and turbulence from fittings.
Calculating a Pump's Maximum Suction Head
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Influence of Viscosity on Head Loss
Influence of Viscosity on Head Loss

Influence of Viscosity on Head Loss (US Customary Units) Influence of Viscosity on Head Loss Context: Fluid Flow in Pipes. Transporting fluids (water, oil, gas, etc.) through pipelines is ubiquitous in industry and daily life. During this flow, the fluid rubs against...

Total Head Loss in a Simple Pipe System
Total Head Loss in a Simple Pipe System

Exercise: Total Head Loss in a Simple Pipe System Calculating Total Head Loss in a Simple Pipe System Context: Water Flow in Pipes. In hydraulics, particularly in civil engineering fields like potable water supply or sanitation systems, it is crucial to understand and...

Calculating Singular Head Loss for a Valve
Calculating Singular Head Loss for a Valve

Exercise: Singular Head Loss for a Valve Calculating Singular Head Loss for a Valve Context: Singular Head LossLocalized energy losses in a hydraulic circuit, caused by pipe fittings (elbows, valves, tees, etc.) that disrupt the fluid flow.. In any hydraulic circuit,...

EGL and HGL Calculation
EGL and HGL Calculation

Exercise: EGL and HGL Calculation Calculating the Energy Grade Line (EGL) and Hydraulic Grade Line (HGL) Context: The study of pressurized pipe flowFlow of a fluid that completely fills a closed conduit. The pressure can be greater or less than atmospheric pressure.....

Comparison of Hydraulic Head Loss
Comparison of Hydraulic Head Loss

Exercise: Comparing Hydraulic Head Loss Comparison of Hydraulic Head Loss Context: Fundamentals of Pressurized Pipe Flow. Transporting fluids in pipes is a pillar of civil and industrial engineering. However, as a fluid flows, it inevitably loses energy due to...

Head Loss Calculation with Hazen-Williams
Head Loss Calculation with Hazen-Williams

Exercise: Head Loss Calculation with Hazen-Williams Head Loss Calculation with Hazen-Williams Context: Sizing a Water Supply Pipeline. One of the major challenges in hydraulic engineering is transporting water over long distances efficiently. To do this, it's crucial...

Influence of Viscosity on Head Loss
Influence of Viscosity on Head Loss

Influence of Viscosity on Head Loss (US Customary Units) Influence of Viscosity on Head Loss Context: Fluid Flow in Pipes. Transporting fluids (water, oil, gas, etc.) through pipelines is ubiquitous in industry and daily life. During this flow, the fluid rubs against...

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